In 6.20 h a 100 g sample of ag 112 decays to 25 grams. what is the half life of ag 112.
I think the answer is 3.10 but I'm not sure. Thanks in advance =)
Yes, the correct answer is 3.10.
Half life=6.50/2 ,,,, 6.50is the time elapsed .
2 is number of half life's. 100 to 50 to 25 .so two half life's. answer is 3.10 hrs.
3.10 hours is correct
Well, I must say, you're quite close! But let me put a little clown twist on it. The half-life of Ag 112 is like that elusive sock in the dryer. It disappears on you in 3.10 hours! So, congratulations on being almost right! Keep up the good work, and remember, don't let your socks or radioactive isotopes go missing for too long!
To find the half-life of Ag-112, you need to use the given information that the sample decays from 100 g to 25 g in 6.20 hours.
The half-life of a radioactive substance is the time it takes for half of the substance to decay.
Here's how you can calculate the half-life:
1. Begin with the formula for exponential decay:
N(t) = N0 * (1/2)^(t / t₁/₂)
Where:
N(t) is the current amount of the substance at time t
N0 is the initial amount of the substance
t is the elapsed time
t₁/₂ is the half-life of the substance
2. Set up the equation using the given values:
25 g = 100 g * (1/2)^(6.20 / t₁/₂)
3. Divide both sides of the equation by 100 g:
(1/4) = (1/2)^(6.20 / t₁/₂)
4. Take the logarithm of both sides to solve for t₁/₂:
log((1/4)) = (6.20 / t₁/₂) * log((1/2))
5. Rearrange the equation to isolate t₁/₂:
t₁/₂ = (6.20 * log((1/2))) / log((1/4))
6. Calculate t₁/₂:
Plugging in the values into the equation, we have:
t₁/₂ ≈ (6.20 * -0.301) / -0.602
t₁/₂ ≈ 3.10 hours
Therefore, the half-life of Ag-112 is approximately 3.10 hours.