I blanked how to solve this:
How many grams of carbon dioxide are produced when 2.5 grams of sodium bicarbonate reacts with excess citric acid according to:
3NaHCO3+H3C6H5O7 -> Na3C6H5O7+3CO2+3H2O
Could you include the steps, please? Thanks.
Here is a worked example.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To solve this problem, we can follow these steps:
Step 1: Determine the molar mass of sodium bicarbonate (NaHCO3) and carbon dioxide (CO2).
- The molar mass of NaHCO3 can be calculated as:
- (1 * Atomic mass of Na) + (1 * Atomic mass of H) + (1 * Atomic mass of C) + (3 * Atomic mass of O)
- The molar mass of CO2 can be calculated as:
- (1 * Atomic mass of C) + (2 * Atomic mass of O)
Step 2: Convert the given mass of sodium bicarbonate (2.5 grams) to moles.
- This can be done by dividing the given mass by the molar mass of NaHCO3 calculated in Step 1.
Step 3: Use the balanced equation to determine the mole ratio between sodium bicarbonate (NaHCO3) and carbon dioxide (CO2).
- According to the balanced equation, we have:
- 3 moles of NaHCO3 produce 3 moles of CO2
Step 4: Convert the moles of sodium bicarbonate (calculated in Step 2) to moles of carbon dioxide using the mole ratio from Step 3.
Step 5: Convert the moles of carbon dioxide (calculated in Step 4) to grams.
- This can be done by multiplying the moles of CO2 by the molar mass of CO2 calculated in Step 1.
By following these steps, you should be able to calculate the number of grams of carbon dioxide produced when 2.5 grams of sodium bicarbonate reacts.