How many moles of precipitate were recovered from BaCro4?
What reaction or experiment was performed?
I have no idea.
Is this a question about a lab experiment you were supposed to do?
Probably it is an experiment. moles ppt = grams ppt/molar mass ppt.
To determine the number of moles of precipitate recovered from BaCrO4, you will need to know the mass of the precipitate. Here are the steps to calculate it:
1. Determine the molar mass of BaCrO4 (barium chromate). The molar mass of Ba is 137.33 g/mol, Cr is 51.996 g/mol, and 4 times the molar mass of O (oxygen) is 4 x 16.00 g/mol = 64.00 g/mol. Adding them together, the molar mass of BaCrO4 is 137.33 g/mol + 51.996 g/mol + 64.00 g/mol = 253.326 g/mol.
2. Measure the mass of the precipitate recovered. Let's assume it is 2 grams.
3. Use the formula: Moles = Mass / Molar mass. Plug in the values: Moles = 2 g / 253.326 g/mol = 0.0079 moles (rounded to four decimal places).
Therefore, the number of moles of precipitate recovered from BaCrO4 is approximately 0.0079 moles.