Consider a monohybrid cross between a pure tall plant and a dwarf plant. In F2 generation of this cross 4000 seedlings were produced. How many seedlings will be tall?
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Sra
To determine the number of seedlings that will be tall in the F2 generation of a monohybrid cross between a pure tall plant and a dwarf plant, you need to understand the principles of Mendelian genetics.
In this case, the tall plant is homozygous dominant (TT) for the tall trait, and the dwarf plant is homozygous recessive (tt) for the dwarf trait. When these plants are crossed in the F1 generation, all the offspring will be heterozygous (Tt) for the tall trait.
When the F1 generation plants are self-crossed to produce the F2 generation, the possible genotypes and phenotypes can be determined using a Punnett square:
T t
T | TT Tt
t | Tt tt
According to the Punnett square, the F2 generation can have three genotypic ratios: 1 TT (tall), 2 Tt (tall), and 1 tt (dwarf). Since the tall trait (T) is dominant over the dwarf trait (t), both the TT and Tt genotypes will express the tall phenotype.
Therefore, the number of seedlings in the F2 generation that will be tall is the sum of the seedlings with TT and Tt genotypes.
In this case, out of the 4000 seedlings produced in the F2 generation, the distribution is as follows:
TT (tall): 1/4 x 4000 = 1000 seedlings
Tt (tall): 1/2 x 4000 = 2000 seedlings
So, the total number of seedlings that will be tall is 1000 + 2000 = 3000 seedlings.