if 100g of water at 20 degrees C absorbs 5kj of heat, what amount will the temerature of the water increase?
To determine the temperature increase of the water, we need to use the formula for heat capacity:
Q = m * c * ΔT
Where:
Q = energy absorbed (in Joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)
In this case, we have:
Q = 5 kJ = 5000 J (since 1 kJ = 1000 J)
m = 100 g
c = specific heat capacity for water (which is approximately 4.18 J/g°C)
Rearranging the formula, we can solve for ΔT:
ΔT = Q / (m * c)
Substituting the values:
ΔT = 5000 J / (100 g * 4.18 J/g°C)
ΔT = 11.96 °C (rounded to two decimal places)
Therefore, the temperature of the water will increase by approximately 11.96 °C.