Calculus
posted by Liz .
A car passes by a certain point at time t = 0 hours heading east at 40 miles per hour. At t = 1 hour another car passes by the same point heading north at 50 miles per hour. What is the functiuonthat equals the distance between the two cars?

distance= sqrt[(40t)^2+(50(t1))^2 ]
check my thinking. 
The answer has to be one of the following:
a. L=90t50
b. L= sqrt(4100t)
c. L= sqrt(4100t^2 +5000t +2500)
d. L= sqrt(4100t^25000t + 2500)
e. L= sqrt(90t50) 
And, it is one of those. Can you not do the algebra?

just simplify what bob put you'll get D!
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