Boyle's Law says that the volume of a gas varies inversely with the pressure. When the volume of a certain gas is 4L, the pressure is 165 kPa(kilopascals). What is the volume when the pressure is 60 kPa?
".. the volume of a gas varies inversely with the pressure"
implies that
V =k/P, where k is a constant
given: when V=4, P = 165
4 = k/165
k = 660
so we have : V = 660/P
when P = 60
V = 660/60 = 11
or
the volume of a gas varies inversely with the pressure
V1/V2 = P2/P1
4/V2 = 60/165
60V2 = 660
V2 = 660/60 = 11
Ah, Boyle's Law, always making things inversely proportional. It's like the law of dating - the lower the pressure, the higher the volume of happy conversations. Now, let's calculate this with a touch of humor!
According to Boyle's Law, we have two values: volume and pressure. When volume is 4L, the pressure is 165 kPa. Now, when the pressure is 60 kPa, we need to find the volume.
To solve this, we'll use the formula for Boyle's Law: P1V1 = P2V2.
Let's plug in the values we have:
165 kPa * 4L = 60 kPa * V2.
Now, let's solve for V2. We'll divide both sides by 60 kPa and multiply by 4L:
V2 = (165 kPa * 4L) / 60 kPa.
Calculating this out, we get:
V2 = 11L.
So, when the pressure is 60 kPa, the volume is a grand 11L! Remember, in the world of gases, they may be under pressure, but they can still expand and give you a laugh.
To find the volume when the pressure is 60 kPa, we can use Boyle's Law equation, which states that the pressure and volume of a gas are inversely proportional.
The equation can be written as:
P1 * V1 = P2 * V2
Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume
Given that:
P1 = 165 kPa
V1 = 4 L
P2 = 60 kPa
We can substitute the given values into the equation and solve for V2:
165 kPa * 4 L = 60 kPa * V2
Simplifying the equation:
660 kPa * L = 60 kPa * V2
Dividing both sides of the equation by 60 kPa:
(660 kPa * L) / 60 kPa = V2
Canceling out the units, we find that:
11 L = V2
Therefore, when the pressure is 60 kPa, the volume of the gas is 11 liters.
To solve this problem, we can use Boyle's Law, which states that the product of the initial volume and pressure is equal to the product of the final volume and pressure in an inversely proportional relationship.
Boyle's Law equation is given as follows:
P₁V₁ = P₂V₂
Where:
P₁ = Initial pressure
V₁ = Initial volume
P₂ = Final pressure
V₂ = Final volume
We are given:
Initial volume (V₁) = 4L
Initial pressure (P₁) = 165 kPa
Final pressure (P₂) = 60 kPa
We can solve for the final volume (V₂) using the formula:
V₂ = (P₁V₁) / P₂
Substituting the given values into the equation:
V₂ = (165 kPa * 4L) / 60 kPa
To simplify, we can cancel out the common unit of kilopascals (kPa):
V₂ = (165 * 4) / 60 L
Now, let's calculate the final volume (V₂):
V₂ = (660) / 60 L
V₂ ≈ 11 L
Therefore, when the pressure is 60 kPa, the volume of the gas is approximately 11 liters.