# Chemistry

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3 I- (aq) +H3AsO4 (aq) + 2 H+ = I3- (aq) + H3AsO3 (aq) + H2O (l) is found to be first order with respect to each of the reactants. write the rate law. what is the over all order?

• Chemistry -

rate = k(I^-)(H3AsO4)(H^+)
Since the rate law is first order with respect to EACH reactant, then each exponent for each reactant is 1. The overall order is the sum of each or1+1+1 = 3 overall.

• Chemistry -

first order reaction

## Similar Questions

1. ### Chemistry

To obtain the rate of the reaction 3I-(aq) + H3AsO4(aq) + 2H+(aq) --> I3-(aq) + H3AsO3(aq) + H2O (l) I got that the rate is 1/3 delta [I-]/ delta t = delta [H3AsO4]/ delta t is this correct
2. ### Chemistry

To obtain the rate of the reaction 3I-(aq) + H3AsO4(aq) + 2H+(aq) --> I3-(aq) + H3AsO3(aq) + H2O (l) I got that the rate is 1/3 delta [I-]/ delta t = delta [H3AsO4]/ delta t is this correct
3. ### Chemistry

To obtain the rate of the reaction 3I-(aq) + H3AsO4(aq) + 2H+(aq) --> I3-(aq) + H3AsO3(aq) + H2O (l) I got that the rate is 1/3 delta [I-]/ delta t = delta [H3AsO4]/ delta t is this correct
4. ### Chemistry

To obtain the rate of the reaction 3I-(aq) + H3AsO4(aq) + 2H+(aq) --> I3-(aq) + H3AsO3(aq) + H2O (l) I got that the rate is 1/3 delta [I-]/ delta t = delta [H3AsO4]/ delta t is this correct

1) The decomposition of hydrogen peroxide in solution and in the presence of iodide ion was studied in laboratory, and the following mechanism proposed based on the experimental data. H2O2 + I - = H2O + IO - (slow) H2O2 + IO - = H2O …

1) The decomposition of hydrogen peroxide in solution and in the presence of iodide ion was studied in laboratory, and the following mechanism proposed based on the experimental data. H2O2 + I - = H2O + IO - (slow) H2O2 + IO - = H2O …