A circular loop of area 0.8 m2 is inclined at an angle 60° in a uniform magnetic field of 0.4 Tesla. What is the magnetic flux associated with the loop?
Choose one answer.
a. 0.32 Weber
b. 0.16 Weber
c. 0.28 Weber
d. 0.14 Weber
The flux is the product of the area, the field, and the sine of the angle between the field and the nromal to the loop.
It is not clear from your question what angle they are talking about.
b. 0.16 Weber
To determine the magnetic flux associated with the circular loop, we can use the formula:
Magnetic flux (Φ) = magnetic field strength (B) * area (A) * cosine of the angle between the magnetic field and the normal to the loop.
Given:
Area of the loop (A) = 0.8 m2
Angle (θ) = 60°
Magnetic field strength (B) = 0.4 Tesla
First, we need to find the value of the cosine of the angle, which can be calculated by taking the cosine of 60°:
Cos(60°) = 0.5
Now, we can substitute the given values into the formula to find the magnetic flux:
Φ = B * A * cos(θ)
= 0.4 Tesla * 0.8 m2 * 0.5
= 0.16 Weber
Therefore, the magnetic flux associated with the loop is 0.16 Weber (option b).