Question

rewrite as an equivalent loganthmic

e-^2=0.1353

Answer 1

Given:

e^(-2)=0.1353
Take (natural) log on both sides:
log(e^(-2))=log(0.1353) ...(1)

Since log(base n)n^x = x
then log_ee^x = x

We rewrite the previous expression (1) as
-2 = log_e(0.1353)
or
log_e(0.1353) = -2