algebra 2

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What is
36x^3-33x^2-33x-6/9x+3

  • algebra 2 -

    With parentheses properly inserted, it should read:
    (36x^3-33x^2-33x-6)/(9x+3)
    Try factorizing both numerator and denominator and cancel common factors, if possible:
    (36x^3-33x^2-33x-6)/(9x+3)
    =3(3x+1)(4x^2-5x-2)/3(3x+1)
    =4x^2-5x-2

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