algebra 2
posted by nina .
What is
36x^333x^233x6/9x+3

With parentheses properly inserted, it should read:
(36x^333x^233x6)/(9x+3)
Try factorizing both numerator and denominator and cancel common factors, if possible:
(36x^333x^233x6)/(9x+3)
=3(3x+1)(4x^25x2)/3(3x+1)
=4x^25x2