posted by xx .
The following equilibrium concentrations were observed for the Haber process at 127 oC:
[NH3] = 3.1 x 10-2 mol L-1
[N2] = 8.5 x 10-1 mol
[H2] = 3.1 x 10-3 mol
Calculate the value of K at 127 oC for this reaction
for the concentrations I meant
[NH3] = 3.1 x 10^-2 mol
[N2] = 8.5 x 10^-1 mol
[H2] = 3.1 x 10^-3 mol
Concentration is not measured in moles.
I meant mol/L^-1 or whatever the unit is. That's what the question had.
Umm can you please help me with this question?