How do i find X in e^(0.50/x) on a scientific calc?
do I use LN, and if so, could you pls tell me how I can plug it in?
actually the e is a variable with the value 1.56x10^20
So, I have to find X in [1.56x10^20]^(0.50/X)
To find an unknown (x), you need an equation.
What has been supplied is an expression containing x. Does it equal some value?
its actually a physics question
q=(2 coul)[1.56x10^20]^([0.50/sec][t])
t=time in sec.
The full question:
The charge (in coul.) on an object increases according to q=(2 coul)e^[(o.05/sec)(t)], where t=time in sec. At how many sec. is the object deficient 1.56x10^20 electrons (from neutral)?
A 0 B 12.56 C 21.94 D 28 E 42.21 F 50.5
One coulomb = 6.24150965(16)×10^18 electrons.
1.56*10^20 electrons
= 1.56*10^20/6.24150965(16)×10^18 coulombs
=25 coulombs
So the equation becomes:
25 coulombs = 2 coulombs * e^(0.05t)
e^(0.05t) = 25/2=12.5
take ln on both sides:
0.05t = ln 12.5 = 2.526
t = 2.526/0.05 = 50.5 sec.
To find the value of X in the expression e^(0.50/x), you can indeed use the natural logarithm (ln) function on a scientific calculator. Let me explain how you can calculate it step by step:
1. First, turn on your scientific calculator and locate the ln button. It is usually labeled as "ln" or "ln(x)" and is often found on the same key as the natural logarithm function.
2. Enter the exponent expression: In this case, you would enter 0.50/x. Since the calculator evaluates expressions from left to right, you may need to use parentheses to ensure correct calculation. For example, you can enter "0.50 / x" or "(0.50) / x" to represent the division.
3. Press the ln button to find the natural logarithm of 0.50/x. Your calculator will then display the numerical value of ln(0.50/x).
4. Finally, rearrange the equation to solve for x. Since e^(ln(x)) cancels each other out (as they are inverse operations), you can rewrite the equation as e^(0.50/x) = x. Once you have the numerical value of ln(0.50/x), you can use it to solve for x. This may involve further algebraic manipulation or trial and error.
Please note that once you find the value of ln(0.50/x), it is important to carefully consider the context and constraints of your problem to determine the appropriate value for X.