Trigonometry
posted by Randolph .
solve:
tan x/2= sqrt3/ 3

tan x/2 = √3/3
i recognize the 306090 triangle, where
tan 30° = 1/√3 = √3/3
so x/2 = 30° or x/2 = 210° by CAST
x = 60° or x = 420°
or
in radians, x = π/3 or x = 7π/3
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