# Algebra

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Find an equation of the line containing pair of points
(1/6, 1/3) and (5/6, 3)
I can't seem to figure out the slope right, which apparently is 5. How does one get a five slope out of all these fractions?!!!
To find the slope 3-1/3 = 8/3 over
5/6 - 1/6 = 4/6 = 2/3
What am I doing wrong?

• Algebra -

so the numerator is 8/3 and the denominator is 2/3

then (8/3) / (2/3)
= (8/3)(3/2) = 4 , not 5

equation: y = 4x + b
plug in (1/6, 1/3)
1/3 = 2/3 + b
b = -1/3

y = 4x - 1/3

• Algebra -

Hi,
I got four also, but the program I ran gave me the answer as 5x +7/6. What bothers me about the program is we have to take tests with the program and the problems don't work out to be what our workbook says.

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