Are these equations balanced correctly? Zn(s) + 2

Na+(aq) + 2 OH-(aq) + 2 H2O(l) → Zn(OH)42-(aq) + 4 Na+(aq) + H2(g)

2 C3H6(g) + 5 O2(g) → 6 CO2(g) + 8 H2O(l)

2nd one no. YOu have 12 H on left ond 16 on right. You have 10 O on left and 20 on right.

1st one no. You have
2 Na ions on left and 4 Na ions on right.
zero charge on left and 2+ charge on right.

Zn(s) + Na+(aq) + 2 OH-(aq) + 2 H2O(l) → Zn(OH)42-(aq) + Na+(aq) + H2(g)

2C3H6(g) + 4O2(g) → 6CO2(g) + 6H2O(l)

Would this be right?

I don't understand. You can check these yourself and know if you are right or wrong without asking any help.

1. looks ok to me.
2. Count the O atoms. I count 8 O atoms on the left and I count 18 on the right.
Here is how I do them.
C3H6 + O2 ==> CO2 + H2O

I need 3C on the right so I place a coefficient of 3 for CO2 on the right.
C3H6 + O2 --> 3CO2 + H2O

How many H do I need on the right? 6 so I place a 3 in front of H2O like this.
C3H6 + O2 --> 3CO2 + 3H2O

C is ok. H is ok. Now I count up O on the right which I need (because I can make that any number I wish on the left). I need 6 O from CO2 and 3 from H2O for a total of 9 O atoms. So I multiply O2 by 9/2 (9/2 x 2 = 9).
C3H6 + 9/2 O2 ==> 3CO2 + 3H2O

We usually don't like to keep fractions in the final equation so I multiply the entire equation through by 2.
2C3H6 + 9 O2 ==> 6CO2 + 6H2O
Now we check it.
6C on left and 6 on right.
12 H on left and 12 on right.
18 O on left and 18 on right (6*2=12 from 6CO2 and 6*1=6 from 6H2O and 12+6=18 total).

To check if the equations are balanced correctly, we need to ensure that the number of atoms on both sides of the equation is the same. Let's start with the first equation:

Zn(s) + 2 Na+(aq) + 2 OH-(aq) + 2 H2O(l) → Zn(OH)4^2-(aq) + 4 Na+(aq) + H2(g)

On the left side, we have:
- 1 Zn atom
- 2 Na atoms
- 2 O atoms (from OH-)
- 2 H atoms (from H2O)

On the right side, we have:
- 1 Zn atom
- 4 Na atoms
- 4 O atoms (from OH- and Zn(OH)4^2-)
- 2 H atoms (from H2)

To balance the equation, we need to have the same number of atoms on each side. Here's the balanced equation:

Zn(s) + 2 Na+(aq) + 2 OH-(aq) + 2 H2O(l) → Zn(OH)4^2-(aq) + 4 Na+(aq) + 2 H2(g)

Now, let's check the second equation:

2 C3H6(g) + 5 O2(g) → 6 CO2(g) + 8 H2O(l)

On the left side, we have:
- 6 C atoms (2 × 3 from C3H6)
- 12 H atoms (2 × 6 from C3H6)
- 10 O atoms (5 × 2 from O2)

On the right side, we have:
- 6 C atoms (from 6 CO2)
- 16 H atoms (8 × 2 from 8 H2O)
- 12 O atoms (from 6 CO2 and 8 H2O)

To balance the equation, we need to have the same number of atoms on each side. Here's the balanced equation:

2 C3H6(g) + 9 O2(g) → 6 CO2(g) + 6 H2O(l)

Now both equations are correctly balanced.