When a charge of -4 x 10 to the minus 3 coulombs is moved between two points in an electric field, 0.8 joules of work are done on the charge. The potential difference between the two points is 300 V.
No, it isn't. The potential difference is E/Q = 0.8/4*10^-3 = 200 V
Is this supposed to be a true/false question? Or do you just want your answer checked?
To find the potential difference between two points, you can use the formula:
Potential difference (V) = Work done (W) / Charge (Q)
In this case, the work done on the charge is given as 0.8 joules, and the charge is -4 x 10^-3 coulombs. Thus, the potential difference can be calculated as follows:
V = 0.8 J / (-4 x 10^-3 C)
To divide by a number in scientific notation, you can make the base of the numerator and denominator the same. In this case, you need to multiply the denominator by 10^3 to get the base of 10^0:
V = 0.8 J / (-4 x 10^-3 C) * (10^3 C / 10^3 C)
Now you can simplify:
V = (0.8 J * 10^3 C) / (-4 x 10^-3 C * 10^3 C)
Multiplying the numbers, you get:
V = (0.8 J * 10^3 C) / (-4 C * 10^-3 C * 10^3)
Simplifying the exponents, you get:
V = (0.8 J * 10^3 C) / (-4 C * 10^0)
Calculating the numerator and denominator independently, you get:
V = (-320 J) / (-4 C)
Finally, dividing the numerator by the denominator:
V = 80 V
So, the potential difference between the two points is 80 volts (V).