trig

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sec(90degrees -theta)

  • trig -

    sec(90 -theta) = 1/cos(90 - theta)
    = 1/(cos90 cos theta + sin 90 sin theta)
    = 1/sin theta
    = csc theta

    You could get the same result by considering a right triangle. The sec of one acute angle is the csc of the other.

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