Replace each equation with constants to complete the square and form a true equation

x^2+2x+--=(x+---)^2

how to do this: first, from the equation, we get b or the numerical coefficient of x.

from the given, b = 2.
then divide this by 2:
2/2 = 1
and square it:
1^2 = 1
thus, the number that we're looking for is 1:
x^2 + 2x + 1 =(x + 1)^2

hope this helps~ :)

To complete the square for the equation x^2 + 2x + ___, we need to determine what value(s) should be filled in the blanks.

Step 1: Take half of the coefficient of the x term and square it.
Half of 2 is 1, and 1 squared is 1.

Step 2: Replace the first blank with the value obtained in Step 1.
So, we place 1 in the first blank: x^2 + 2x + 1.

Step 3: Replace the second blank with the value obtained in Step 1, outside parentheses.
So, we place 1 outside the parentheses: (x + 1)^2.

The completed square for the given equation is (x + 1)^2. Now we can form a true equation by replacing the original equation with the completed square:

x^2 + 2x + 1 = (x + 1)^2