Consider the reaction:
N2(g) + 3H2(g) ¡ú 2NH3(g)
question: calculate ¦¤S¡ã in J¡¤K-1.
I can't interpret the symbolism.
To calculate the entropy change (ΔS), we need to consider the change in entropy of the reactants and the products. The equation you provided represents the reaction of nitrogen gas (N2) and hydrogen gas (H2) to form ammonia gas (NH3).
The first step is to determine the entropies of the individual species involved in the reaction. The molar entropies of N2, H2, and NH3 can be found in tables or reference sources. Let's assume:
S(N2) = x J/mol·K
S(H2) = y J/mol·K
S(NH3) = z J/mol·K
The next step is to calculate the change in entropy (ΔS) using the equation:
ΔS = ΣnS(products) - ΣnS(reactants)
In this equation, ΣnS(products) refers to the sum of the molar entropies of the products multiplied by their stoichiometric coefficients, and ΣnS(reactants) refers to the sum of the molar entropies of the reactants, also multiplied by their stoichiometric coefficients.
For your reaction, the stoichiometric coefficients are:
N2: 1
H2: 3
NH3: 2
Substituting the values:
ΔS = (2 * z) - (1 * x + 3 * y)
Simplifying further:
ΔS = 2z - x - 3y
To obtain the numerical value of ΔS, you need the values of x, y, and z from reference sources. Once you have these values, substitute them into the equation and perform the calculation.