advance functions

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will someone please help me with the question i posted earlier ? :(

  • advance functions -

    log2=log(x+5)-1

    log 2 - log (x+5) = -1

    log (2/(x+5)) = -1

    10^log (2/(x+5)) = 10^-1 = 0.1

    so
    2/(x+5) = 0.1
    2 = .1 x + .5
    1.5 = .1 x
    x = 15

  • advance functions -

    oh right on! thanks!

  • advance functions -

    You are welcome :)

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