Jackie and two friends are drawing from a bag that contains savings cards for a popular store. There are twenty 10% off cards, ten 15% off cards, six 20%off cards, and four 50% off cards. What is the probability that jackie will choose a 50 % off card as her third choice? Assume that her friends did not draw a 50% off card?
Total number of cards left
=20+10+6+4 - 2
=38
Number of 50% off cards
= 4
Therefore probability of drawing a 50% off card
= 4/38
= ?
To find the probability that Jackie will choose a 50% off card as her third choice, we need to consider the total number of cards and the number of 50% off cards remaining in the bag.
First, let's calculate the total number of cards. We have:
20 (10% off cards) + 10 (15% off cards) + 6 (20% off cards) + 4 (50% off cards) = 40 cards
Now, let's consider the probability of Jackie choosing a 50% off card as her third choice. We know that her friends did not draw a 50% off card, so we need to consider the remaining number of 50% off cards in the bag.
After Jackie's friends draw, the number of 50% off cards remaining in the bag is 4.
Now, Jackie will choose one card at a time, three in total. Thus, the probability that she will choose a 50% off card as her third choice can be calculated as follows:
(Number of 50% off cards remaining in the bag) / (Total number of cards remaining in the bag) = 4 / 40 = 1 / 10 = 0.1
Therefore, the probability that Jackie will choose a 50% off card as her third choice is 0.1 or 10%.
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Cow utter
4 3 12 2
- * - = - = -
38 3 114 19
=20+10+6+4
=40 cards
= Friends -2 cards
=38 cards
=4 50%
=P 4/38, 1/19