math
posted by Joe .
A box containing Munchkins contains chocolate and glazed donut holes. If Gloria ate 2 chocolate Munchkins, then 1/11 of the remaining Munchkins would be chocolate. If Gloria added 4 glazed Munchkins to the box, 1/7 of the Munchkins would be chocolate. How many Munchkins are in the original box?

If Gloria added 4 glazed Munchkins to the box, the proportion of chocolate increased from 1/11 to 1/7?
You will get negative numbers as answers.
Below, I assume you have switched the two proportions between 1/11 and 1/7.
If my guess proves to be wrong, the solution method remains the same.
G = glazed
C = chocolate
7(C2) = G + C2
11(C2) = G+4 + C2
or
6CG =12
10CG = 24
Solve for G and C to get
G=6, C=3