i need help with just one question, and if i get it, ill be able to do the rest. Okay so its saying let height of a box be 4x+1, width be x-3, and length be 2x. Find the volume.
So what do i do? how do i start solving this? its polynomials
H=Hight
W=Width
L=Length
V=Volume
V=H*W*L
V=(4x+1)*(x-3)*2x
V=[4x*x + 1*x + 4x*(-3) +1*(-3)]*2x
V=(4x^2 +x -12x -3)*2x
V=(4x^2 -11x -3)*2x
V=4x^2*2x - 11x*2x -3*2x
V=8x^3 -22x^2 -6x
thank you so much.
To find the volume of the box, you need to multiply the height, width, and length together. In this case, the height is 4x + 1, the width is x - 3, and the length is 2x.
To find the volume:
1. Write the formula for the volume of the box: Volume = Length x Width x Height.
2. Substitute the given expressions for the length, width, and height into the formula.
Volume = (2x) x (x - 3) x (4x + 1).
3. Simplify the equation by multiplying the terms together using the distributive property and combining like terms.
Volume = 8x^2 - 24x + 2x^2 - 6x.
4. Combine like terms:
Volume = (8x^2 + 2x^2) + (-24x - 6x).
Volume = 10x^2 - 30x.
5. The resulting expression, 10x^2 - 30x, represents the volume of the box.
So, the volume of the box is given by the polynomial 10x^2 - 30x.