What is the wavelength of the emitted photon, when the electron in the hydrogen atom makes a transition from the ni = 5 state to the nf = 3 state?
(1/wavelength) = R(1/3^2 - 1/5^2)
R = Rydberg constant.
is the answer 780373.3333
No but I think it's close to the reciprocal of that number.
1/wavelength = 0.07111(R)
To calculate the wavelength of the emitted photon when an electron in a hydrogen atom makes a transition from the ni = 5 state to the nf = 3 state, we use the Rydberg formula.
The Rydberg formula is given as:
1/λ = R * (1/ni^2 - 1/nf^2)
Where:
- λ is the wavelength of the emitted photon
- R is the Rydberg constant (approximately 1.097 x 10^7 m^-1)
- ni is the initial state or principal quantum number
- nf is the final state or principal quantum number
By substituting the values into the formula, we get:
1/λ = (1.097 x 10^7 m^-1) * (1/5^2 - 1/3^2)
Solving this equation will give us the reciprocal of the wavelength (1/λ). To find the actual wavelength, we can take the reciprocal of the result:
λ = 1 / (1/λ)
By performing the calculations, the wavelength (λ) can be determined.