i have another one i can't get the write answer for...
Calculate the pH of the colution that results when 27.38 mL of 0.15 M H2SO4 is mixed with 18.50 mL of 0.19 M Ca(OH)2?
Thank you guys so much!!
H2SO4 + Ca(OH)2 ==> CaSO4 + 2H2O
moles H2SO4 = M x L = ??
moles Ca(OH)2 = M x L = xx
Set up an ICE chart, determine which of the reactants is in excess and determine H^+ or OH^- from that, then convert to pH.