If 130.0 g Zn reacts, what mass of ZnCL2 are produced?
Follow the steps of this example.
http://www.jiskha.com/science/chemistry/stoichiometry.html
Well, if 130.0 g of Zn react, you should be prepared for some transformation! It's like when you put a slice of bread in a toaster and it comes out as toast – except in this case, it's zinc turning into zinc chloride. Now, let's get calculating!
The molar mass of Zn is about 65.38 g/mol, and the molar mass of ZnCl2 is approximately 136.29 g/mol. To find the mass of ZnCl2, we need to consider the molar ratio between Zn and ZnCl2.
Looking at the balanced chemical equation, we find that 1 mole of Zn reacts to produce 1 mole of ZnCl2. This means that the molar ratio is 1:1.
So, if we have 130.0 g of Zn, we can calculate the number of moles by dividing the mass by the molar mass:
130.0 g Zn / 65.38 g/mol = 1.9873 mol Zn
Since the molar ratio is 1:1, we know that the number of moles of ZnCl2 produced will also be 1.9873 mol.
Now, let's find the mass of ZnCl2 using the molar mass:
1.9873 mol ZnCl2 * 136.29 g/mol = 270.89 g
Voila! After the reaction, approximately 270.89 grams of ZnCl2 will have hilariously popped out.
To determine the mass of ZnCl2 produced when 130.0 g of Zn reacts, we need to consider the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction between Zn and Cl2 to form ZnCl2 is:
Zn + Cl2 → ZnCl2
From the equation, we can see that the stoichiometric ratio between Zn and ZnCl2 is 1:1. This means that for every 1 mole of Zn, we will produce 1 mole of ZnCl2.
To find the mass of ZnCl2 produced, we need to convert the given mass of Zn to moles using the molar mass of Zn, and then use the stoichiometric ratio to find the corresponding mass of ZnCl2.
The molar mass of Zn is 65.38 g/mol, and the molar mass of ZnCl2 is 136.29 g/mol.
Step 1: Convert the given mass of Zn to moles.
Moles of Zn = Given mass of Zn / Molar mass of Zn
Moles of Zn = 130.0 g / 65.38 g/mol
Moles of Zn = 1.987 moles (rounded to 3 decimal places)
Step 2: Use the stoichiometric ratio to find the moles of ZnCl2 produced.
From the balanced equation, we know that 1 mole of Zn produces 1 mole of ZnCl2.
Moles of ZnCl2 = Moles of Zn
Moles of ZnCl2 = 1.987 moles (rounded to 3 decimal places)
Step 3: Convert the moles of ZnCl2 to mass.
Mass of ZnCl2 = Moles of ZnCl2 × Molar mass of ZnCl2
Mass of ZnCl2 = 1.987 moles × 136.29 g/mol
Mass of ZnCl2 = 270.33 g (rounded to 2 decimal places)
Therefore, when 130.0 g of Zn reacts, approximately 270.33 g of ZnCl2 are produced.
To determine the mass of ZnCl2 produced when 130.0 g of Zn reacts, we need to use the concept of stoichiometry and the balanced chemical equation for the reaction.
Let's assume the balanced chemical equation for the reaction between Zn and ZnCl2 is:
Zn + 2 HCl -> ZnCl2 + H2
From the equation, we can see that 1 mole of Zn reacts with 1 mole of ZnCl2. So, to find the number of moles of ZnCl2 produced, we need to convert the given mass of Zn to moles.
To convert mass to moles, we use the molar mass of Zn. The molar mass of Zn is 65.38 g/mol.
Now we can calculate the number of moles of Zn:
moles of Zn = mass of Zn / molar mass of Zn
= 130.0 g / 65.38 g/mol
≈ 1.987 mol
According to the balanced equation, 1 mole of Zn reacts to produce 1 mole of ZnCl2. Therefore, the number of moles of ZnCl2 produced is also 1.987 mol.
Finally, to find the mass of ZnCl2 produced, we can multiply the number of moles of ZnCl2 by its molar mass. The molar mass of ZnCl2 is the sum of the molar masses of zinc and chlorine.
Molar mass of ZnCl2 = (molar mass of Zn) + 2*(molar mass of Cl)
= (65.38 g/mol) + 2*(35.45 g/mol)
= 136.28 g/mol
mass of ZnCl2 = moles of ZnCl2 * molar mass of ZnCl2
≈ 1.987 mol * 136.28 g/mol
≈ 270.13 g
Therefore, when 130.0 g of Zn reacts, approximately 270.13 g of ZnCl2 are produced.