Question

Write an equation of the line that is perpendicular to the line y=2x-1 and passes throgh the point (0,-3)

Answer 1

m = 2

so
m' = -1/2 = slope of new line
so
y = (-1/2)x + b
-3 = (-1/2)(0) + b
b = -3
so
y = (-1/2) x - 3
or
2y = -x - 6