Advanced algebra
posted by Denice .
How do i simplify this complex fraction?
(x+3)/(3x^2)/(6x^2)/[(x+3)^2]

according to the order of operation,
in a chain of division, you divide from left to right, in the order in which the division occurs.
e.g.
13÷2÷6÷4 = .25
or
= 12*(1/2)*(1/6)*(1/4) = .25
so How do i simplify this complex fraction?
(x+3)/(3x^2)/(6x^2)/[(x+3)^2]
= (x+3) (1/(3x^2)(1/6x^2)(1/(x+3)^2
= 1/(18x^4(x+3)) 
Isn't there a different method you're sposed to use? like finding a common denominator? im thankful that your helping me but all those number got a little confusing... what if i said it looked more like this
the dash mark is a division symbol... this is what it looks like on my paper.
x+3

3x^2

6x^2

(x+3)^2 
You don't need common denominators in division or multiplication.
If the fraction is written as a staggered layer of expressions, the division bar should have different length to establish the order of division.
If all the bars are the same length, then the simplification I used above is valid
In other words, the longest bar determines the prime division.