math
posted by Priya .
what is inverse of this funtion
f(x)=(1 / 3)^x?
I think the answer is
f1(x)= log base 1/3 of x, but i know im wrong... please help!!! THANK YOU

Three steps to finding the inverse:
1. interchange x and y.
2. solve for y in terms of x.
3. evaluate f^{1}(f(x)) to verify that it gives x as the result.
0. y=(1/3)^x
1. x=(1/3)^y
2. log(x)=ylog(1/3)
=> y=log(x)/log(1/3)=log(x)/log(3)
or
f^{1}(x)=log(x)/log(3)
3.
y(f(x))
=y((1/3)^x)
=log((1/3)^x)/(log(3)
=xlog(1/3)/log(3)
=x OK 
THANKS ALOT... I GET IT NOW!!!!!!

You're welcome!
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