geometry
posted by JOY .
How do you find the lateral area and surface area of a right prism whose height is 10 ft and whose base is a rombus with diagonals 12 ft and
12sq root of 3 ( DON'T KNOW HOW TO PUT SQROOT 3 IN)

The area of a rhombus is 1/2 the product of the diagonals.
The top and bottom of your prism are rhombuses with areas of 60 sqrt3 ft^2, EACH.
The four rectangular sides of the prism each have areas of
(height)*[(a/2)^2 + (b/2)^2]
where a and b are the rhombus diagonal lengths. The term in brackets is the rhombus side length, and equals 12 feet in this case.
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