what is the power dissipated by the parallel circuit shown below?

r1 is 100 ohms r2 is 100 ohms r3 is 100 ohms e= 40 v

There is no circuit shown below.

If all three resistors are in parallel, add V^2/R for each resistor to get the total power, with V = 40 v for each one.

To calculate the power dissipated by the parallel circuit, we need to use Ohm's Law and the formula for power (P = I^2 * R). Here are the steps to find the power dissipated:

Step 1: Calculate the total resistance (RT) of the parallel circuit.
The total resistance of a parallel circuit can be calculated using the formula:
1/RT = 1/R1 + 1/R2 + 1/R3 + ...

In this case, since all resistors have the same value of 100 ohms, we can calculate RT as follows:
1/RT = 1/100 + 1/100 + 1/100
1/RT = 3/100
RT = 100/3 ohms

Step 2: Calculate the total current (IT) flowing through the circuit.
We can use Ohm's Law to calculate the total current by dividing the voltage (e) by the total resistance (RT).
IT = e / RT
IT = 40V / (100/3) ohms
IT = 120/100
IT = 1.2 A

Step 3: Calculate the power dissipated by each resistor.
Since the resistors are in parallel, the voltage across each resistor is the same (e = 40V).

For each resistor, we can calculate the power dissipated using the formula:
P = I^2 * R

For R1: P1 = I^2 * R1 = IT^2 * R1 = 1.2^2 * 100 = 1.44 * 100 = 144 watts
For R2: P2 = I^2 * R2 = IT^2 * R2 = 1.2^2 * 100 = 1.44 * 100 = 144 watts
For R3: P3 = I^2 * R3 = IT^2 * R3 = 1.2^2 * 100 = 1.44 * 100 = 144 watts

Step 4: Calculate the total power dissipated by the circuit.
Since the resistors are in parallel, the total power dissipated is the sum of the power dissipated by each resistor.
Total power dissipated = P1 + P2 + P3 = 144 + 144 + 144 = 432 watts

Therefore, the power dissipated by the parallel circuit is 432 watts.

To determine the power dissipated by the parallel circuit, you first need to calculate the total resistance of the circuit. In a parallel circuit, the total resistance (Rp) can be calculated using the following formula:

1/Rp = 1/R1 + 1/R2 + 1/R3

In this case, since all resistors have the same value (100 ohms), the formula simplifies to:

1/Rp = 1/100 + 1/100 + 1/100 = 3/100

Now, to find Rp, you can invert both sides of the equation:

Rp = 100/3 ohms

Once you have the total resistance, you can calculate the current flowing through the circuit using Ohm's Law:

I = E/Rp

Where:
I is the current (in amps)
E is the voltage (in volts)
Rp is the total resistance (in ohms)

Substituting the given values, we get:

I = 40 V / 100/3 ohms = (40 V) * (3/100 ohms) = 1.2 A

Now that you have the current, you can calculate the power dissipated by each resistor using the formula:

P = I^2 * R

For each resistor, since the resistance is the same (100 ohms), the power dissipated is:

P = (1.2 A)^2 * 100 ohms = 1.44 * 100 = 144 watts

Therefore, the power dissipated by the parallel circuit shown is 144 watts.