# computer science

posted by .

Hi,

i need to calculate download time for file which is 4GB and the speed is 43.2 kbps.

i know i have to divide file size by the speed and to change GB to KB but not sure how to change GB to kbps?

• computer science -

Kb means 1000 bytes
MB = 1000 KB
GB = 1000 MB = 1000000Kb

so 4 GB / 43.2 kb/s = 1000000/(43.2 kb/sec)
= 23148.1 seconds

divide by 60 to get into minutes, then by 60 again to get it into hours.

• computer science -

File sizes are given in bytes, while download speeds are given in bits.

4 GB = 4*1024 MB = 4*1024^2 KB = 4*1024^3 Bytes - 4*1024^3*8 bits.

43.2kbps = 43.2*1000 bits per second.

The time required is 795.364s, or 220.935 hours.

Note that 43.2kbps is quite a low bandwidth.

## Similar Questions

1. ### computer science

Hi, I need to design a state machine for a simple CPU. The cpu has a word size of 4 bits, 4 registers, and 2 register ports (A and B) which go to a ‘181 ALU. Our data-input device consists of two DIP switches, which go to the data-in …
2. ### computer

Why adding only characters to a text file may increase the file's size by several hundred bytes and at other times may not increase the file's size at all?
3. ### IT computer memory

Can someone check this for me please.. 18 MB of data are to be transmitted over a a megabyte per second connection. How long should the complete transaction take, to the nearest 0.1s. Size of file / data rate so, 18,874,368 bytes / …
4. ### IT computer memory

Hi, Can someone check this for me please.. 18 MB of data are to be transmitted over a a megabyte per second connection. How long should the complete transaction take, to the nearest 0.1s. Size of file / data rate so, 18MB x 10^6 x …
5. ### IT Data transmission

Hi, Can someone check this for me please.. 18 MB of data are to be transmitted over a 4 megabits per second connection. How long should the complete transaction take, to the nearest 0.1s. Size of file / data rate so, 18MB x 10^6 x …
6. ### computer science

Q1)18 MB of data are to be transmitted over a 4 megabits per second connection. How long should the complete transmission take, to the nearest 0.1 s?