I need a formula for: 0.5 grams of sodium chloride is dissolved to make 0.05 liters of solution. next 0.5 grams of sodium chloride is dissolved to make 0.05 ml of solution. next 670 grams of Pb (C2H3O2)4 are dissolved to make 3.5 ml of solution.
0.5 moles of sodium chloride is dissovled to make 0.05 liters of solution
To find the formula for these solutions, we need to calculate the concentration, or molarity, of each solution. The molarity (M) is defined as the amount of solute (in moles) divided by the volume of the solution (in liters). Here's how we can calculate it step by step:
1. For the first solution:
- Amount of sodium chloride: 0.5 grams
- Volume of the solution: 0.05 liters
To find the molarity, we need to convert grams to moles. We can do this using the molar mass of sodium chloride.
The molar mass of sodium chloride is approximately 58.5 grams per mole (Na = 22.99 g/mol, Cl = 35.45 g/mol).
- Moles of sodium chloride: 0.5 grams / 58.5 grams per mole = 0.00855 moles
- Molarity (M) = 0.00855 moles / 0.05 liters = 0.171 M
2. For the second solution:
- Amount of sodium chloride: 0.5 grams
- Volume of the solution: 0.05 milliliters
First, we need to convert milliliters to liters since molarity is defined in liters.
- Volume of the solution: 0.05 ml / 1000 = 0.00005 liters
- Moles of sodium chloride: 0.5 grams / 58.5 grams per mole = 0.00855 moles
- Molarity (M) = 0.00855 moles / 0.00005 liters = 171 M
Note: The molarity of the second solution is the same as the first because even though the volume is in milliliters, we converted it to liters before calculating the molarity.
3. For the third solution:
- Amount of Pb(C2H3O2)4: 670 grams
- Volume of the solution: 3.5 milliliters
- Volume of the solution: 3.5 ml / 1000 = 0.0035 liters
To find the molarity, we need to convert grams of Pb(C2H3O2)4 to moles using the molar mass of the compound.
The molar mass of Pb(C2H3O2)4 is approximately 443.3 grams per mole (Pb = 207.2 g/mol, C2H3O2 = 82.09 g/mol).
- Moles of Pb(C2H3O2)4: 670 grams / 443.3 grams per mole = 1.512 moles
- Molarity (M) = 1.512 moles / 0.0035 liters = 431.43 M
So the formulas for the given solutions are:
1. The first solution: 0.171 M sodium chloride solution
2. The second solution: 171 M sodium chloride solution
3. The third solution: 431.43 M Pb(C2H3O2)4 solution