# calculus

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Please help. How do I separate the variables in the following differential equation dy/dx=(2/27)(x-3)then square root (x^2-6x+23)/y where (y>0). Then give general solution in implicit form. Thank you so much if you can help.

• calculus -

Check if the initial equation is the following:
dy/dx=(2/27)(x-3)√((x^2-6x+23)/y)

27√(y) dy = 2(x-3)√(x^2-6x+23)dx

Integrate both sides and express y in implicit form.

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