calculus
posted by paul .
Please help. How do I separate the variables in the following differential equation dy/dx=(2/27)(x3)then square root (x^26x+23)/y where (y>0). Then give general solution in implicit form. Thank you so much if you can help.

Check if the initial equation is the following:
dy/dx=(2/27)(x3)√((x^26x+23)/y)
27√(y) dy = 2(x3)√(x^26x+23)dx
Integrate both sides and express y in implicit form.
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