physics - need help
posted by Nilan .
Resistors of 30 ohms and 60 ohms are connected in parallel and joined in series to a 10 ohm resistor.
The circuit voltage is 180 volts.
the voltage of the parallel circuit
the voltage across the parallel circuit
the current through the 10 ohm resistor
The two parallel resistors behave like a single serives resistor of equivalent resistance Req
1/Req = 1/30 + 1/60 = 1/20
So Req = 20 ohms
The total circuit current is
V/R = 180/(20 + 10) = 6 Amps
The voltage drop is 60 V across the 10 ohm resistor and 120 V across the pair of parallel resistors. You seem to be asking the same question twice.
All of the circuit current (6A) goes through the 10 ohm resistor