posted by Josh .
When 1.187g of a metallic oxide is reduced with excess hydrogen, 1.054g of the metal is produced. How do you determine what the metal oxide is?
Ok, so in order to identify the metal oxide, you first start by taking 1.187g-1.054 to find the g of O2. getting .133, you then determine the moles by dividing by mm of O2=.0083125. Then, because it is a metal oxide, multiply the moles of O2 by 2. Then take the 1.054g and divide it by .0083 to get 63.4, which is Copper.