A solution was prepared by adding 0.5283 g of sodium hydroxide to a 50 mL volumetric flask. What is the concentration of sodium hydroxide in moles per liter?
To find the concentration of sodium hydroxide in moles per liter (Molarity or M), you need to divide the number of moles of sodium hydroxide by the volume of the solution in liters.
First, let's calculate the number of moles of sodium hydroxide:
Number of moles = Mass / Molar mass
The molar mass of sodium hydroxide (NaOH) can be found by adding the atomic masses of each element in the compound:
Na (sodium) = 22.99 g/mol
O (oxygen) = 16.00 g/mol
H (hydrogen) = 1.01 g/mol
Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 39.00 g/mol
Now, we can calculate the number of moles of sodium hydroxide:
Number of moles = 0.5283 g / 39.00 g/mol = 0.01351 mol (rounded to five decimal places)
Next, we need to calculate the volume of the solution in liters:
The volume of the solution is given as 50 mL. We need to convert this to liters.
1 mL = 0.001 L
Volume of the solution = 50 mL × 0.001 L/mL = 0.050 L
Finally, we can calculate the concentration of sodium hydroxide in moles per liter:
Concentration (Molarity) = Number of moles / Volume of solution
Concentration (Molarity) = 0.01351 mol / 0.050 L = 0.2702 M (rounded to four decimal places)
Therefore, the concentration of sodium hydroxide in the solution is approximately 0.2702 moles per liter (M).