A solution was prepared by adding 0.5283 g of sodium hydroxide to a 50 mL volumetric flask. What is the concentration of sodium hydroxide in moles per liter?
To find the concentration of sodium hydroxide in moles per liter (M), we first need to calculate the number of moles of sodium hydroxide in the solution. We can use the formula:
Number of moles = Mass / Molar mass
The molar mass of sodium hydroxide (NaOH) is 22.99 g/mol for sodium (Na), 1.01 g/mol for hydrogen (H), and 16.00 g/mol for oxygen (O). Adding them together, we get a molar mass of 39.99 g/mol.
Number of moles = 0.5283 g / 39.99 g/mol
Number of moles = 0.01321 mol
Now, we need to convert the volume of the solution from milliliters (mL) to liters (L). Since there are 1000 mL in a liter, we can convert 50 mL to 0.05 L.
With the number of moles (0.01321 mol) and the volume in liters (0.05 L), we can calculate the concentration (Molarity, M) using the formula:
Concentration (M) = Number of moles / Volume (in liters)
Concentration (M) = 0.01321 mol / 0.05 L
Concentration (M) = 0.2642 M
Therefore, the concentration of sodium hydroxide in the solution is 0.2642 moles per liter (M).