the human body obtains 2000 kj from a candy bar. if this energy were used to vaporize was at 100 degrees celcius, how much water in liters could be vaporized? ??(assume that the density of water is 1.0g/ml)
To find out how much water can be vaporized using the energy obtained from a candy bar, we need to calculate the amount of energy required to vaporize water and then see how many liters of water that energy can vaporize.
The amount of energy required to vaporize water can be calculated using the specific heat formula:
Energy = mass × specific heat × change in temperature
However, in this case, we are looking to vaporize water at 100 degrees Celsius, which is the boiling point of water. At this temperature, water undergoes a phase change from liquid to gas, and additional energy is required to convert it into steam. This is known as the heat of vaporization.
The heat of vaporization of water is approximately 2260 kilojoules per kilogram (kJ/kg).
Now, we can calculate the mass of water that can be vaporized using the energy obtained from the candy bar.
Mass = Energy / Heat of Vaporization
Mass = 2000 kJ / 2260 kJ/kg
Mass = 0.885 kg
Finally, we can convert the mass of water into liters using the density of water.
Density of water = 1.0 g/ml
1 kg = 1000 g
So, 0.885 kg = 885 g
Volume = Mass / Density
Volume = 885 g / 1.0 g/ml
Volume ≈ 885 ml
Since 1 liter is equivalent to 1000 ml, the volume of water that can be vaporized is approximately 0.885 liters.
Therefore, the energy obtained from the candy bar can vaporize approximately 0.885 liters of water.