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find the area of a parallelogram with diagonals of lengths 10 inches and 22 inches that intersect at a 65 degrees angle.

  • geometry -

    We would have 4 equal triangles
    let's look at one of these that contain the 65° angle.
    Height/11 = sin65
    height = 9.969

    area = 4( (1/2)(5)(9.969) = 99.694

  • geometry -

    that last answer posted is wrong

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