express secA in terms of cotA?
can you pleas say how to solve this??
are you sure it wasn't cscA expressed in terms of cotA ?
If so, then
form cos^2 A + cos^2A = 1
divide by sin^2A
cot^2A + 1 = csc^2A
cscA = √(cot^2A + 1)
The way you have it, would make a very messy conversion.
To express secA in terms of cotA, we need to use the trigonometric identity relating secant (sec) and cotangent (cot):
sec^2(A) = 1 + cot^2(A)
Let's solve it step by step:
Step 1: Start with the equation sec^2(A) = 1 + cot^2(A).
Step 2: Rearrange the equation by subtracting cot^2(A) from both sides:
sec^2(A) - cot^2(A) = 1
Step 3: Recognize that sec^2(A) - cot^2(A) can be factored using the difference of squares formula:
(sec(A) + cot(A))(sec(A) - cot(A)) = 1
Step 4: Divide both sides of the equation by (sec(A) - cot(A)):
sec(A) + cot(A) = 1 / (sec(A) - cot(A))
Now you have the expression for sec(A) in terms of cot(A):
sec(A) = 1 / (sec(A) - cot(A))
That's how you solve the expression secA in terms of cotA.