If tanA = the square root of 11, find tan2A
tan 2A = 2tanA/(1 - tan^2 A)
= 2√11/(1 - 11) = =√11/5
To find the value of tan 2A, we can use the double-angle identity for tangent, which states that tan 2A = (2 * tan A) / (1 - tan² A).
Given that tan A = √11, we can substitute this value into the double-angle identity:
tan 2A = (2 * √11) / (1 - (√11)²)
Now, let's simplify the expression:
First, simplify the denominator:
1 - (√11)² = 1 - 11 = -10
Now, simplify the numerator:
2 * √11 = 2√11
Finally, substitute the simplified values back into the expression:
tan 2A = (2 * √11) / (-10)
Therefore, the value of tan 2A is (2√11) / (-10), or more simply, -√11 / 5.