math 117
posted by sue .
A launched rocket has an altitude in meters, given by the polynomial h+vt4.9^2, h is the height in meters v is the velocity in meters per second and t is the number of seconds for which it takes the rocket to become airborne. If the rocket is launched from the top of a tower that is 100 meters and the initial speed is 60 meters per second, what will its height be after 4 seconds rounded to the nearest tenth?

h = 100 + Vo*t + 0.5*gt^2.
h = 100 + 60*4 + 0.5*(9.8)4^2,
h = 100 + 240  78.4 = 261.6m above ground.
h = 261.6  100 = 161.6m above the tower.
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