A launched rocket has an altitude in meters, given by the polynomial h+vt-4.9^2, h is the height in meters v is the velocity in meters per second and t is the number of seconds for which it takes the rocket to become airborne. If the rocket is launched from the top of a tower that is 100 meters and the initial speed is 60 meters per second, what will its height be after 4 seconds rounded to the nearest tenth?

To find the height of the rocket after 4 seconds, we need to substitute the given values into the equation.

Given:
h = 100 meters (the height of the tower)
v = 60 meters per second (the initial velocity)
t = 4 seconds (the time taken to become airborne)

Substituting these values into the equation h + vt - 4.9t^2, we get:
h = 100 + (60 * 4) - 4.9 * (4^2)

First, calculate 4^2 = 16:
h = 100 + (60 * 4) - 4.9 * 16

Next, multiply 60 by 4:
h = 100 + 240 - 4.9 * 16

Then, multiply 4.9 by 16:
h = 100 + 240 - 78.4

Now, add 100 and 240:
h = 340 - 78.4

Finally, subtract 78.4 from 340:
h = 261.6

Therefore, the height of the rocket after 4 seconds will be approximately 261.6 meters when rounded to the nearest tenth.