A launched rocket has an altitude in meters, given by the polynomial h+vt-4.9^2, h is the height in meters v is the velocity in meters per second and t is the number of seconds for which it takes the rocket to become airborne. If the rocket is launched from the top of a tower that is 100 meters and the initial speed is 60 meters per second, what will its height be after seconds rounded to the nearest tenth?
I suggest you start by learning to spell the subject.
Then take the time to type your equations correctly. It is much more likely to be
h = ho + vo*t - 4.9 t^2. You left out t^2 term in any case.
ho is the initial height, 100 m.
vo is the initial speed, 60 m/s
Finally, in your question:
"what will its height be after ___ seconds rounded to the nearest tenth?"
you failed to say how many seconds.
A launched rocket has an altitude in meters, given by the polynomial h+vt-4.9^2, h is the height in meters v is the velocity in meters per second and t is the number of seconds for which it takes the rocket to become airborne. If the rocket is launched from the top of a tower that is 100 meters and the initial speed is 60 meters per second, what will its height be after 4 seconds rounded to the nearest tenth?
To determine the height of the rocket after a certain time, we need to substitute the given values into the polynomial equation.
The polynomial equation is h = h + vt - 4.9t^2.
Given values:
- h (initial height) = 100 meters
- v (initial velocity) = 60 meters per second
- t (time) = the number of seconds for which it takes the rocket to become airborne
Substituting the given values into the equation, we get:
h = 100 + (60 * t) - 4.9 * t^2
To find the rocket's height after a certain time, we will substitute the value of "t" into the equation and solve it.
Since you haven't provided the value of "t" in your question, I'm unable to calculate the exact height of the rocket. Please provide the value of "t" so I can help you find the height after a certain time.