Algbrah
posted by Jessie .
A launched rocket has an altitude in meters, given by the polynomial h+vt4.9^2, h is the height in meters v is the velocity in meters per second and t is the number of seconds for which it takes the rocket to become airborne. If the rocket is launched from the top of a tower that is 100 meters and the initial speed is 60 meters per second, what will its height be after seconds rounded to the nearest tenth?

I suggest you start by learning to spell the subject.
Then take the time to type your equations correctly. It is much more likely to be
h = ho + vo*t  4.9 t^2. You left out t^2 term in any case.
ho is the initial height, 100 m.
vo is the initial speed, 60 m/s
Finally, in your question:
"what will its height be after ___ seconds rounded to the nearest tenth?"
you failed to say how many seconds. 
A launched rocket has an altitude in meters, given by the polynomial h+vt4.9^2, h is the height in meters v is the velocity in meters per second and t is the number of seconds for which it takes the rocket to become airborne. If the rocket is launched from the top of a tower that is 100 meters and the initial speed is 60 meters per second, what will its height be after 4 seconds rounded to the nearest tenth?
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