Jordan has a photograph on his wall that is 3 in. long and 6 in. wide. He takes it to be framed which increases the length and width by 2 in. each. How does getting the picture framed change the amount of wall space needed?
My choice is B- Correct??
Choices
A. the wall needed is increased by 22in^2
B, the wall space needed is increased by 2in^2
C. the wall needed is increased by 16in^2
D. the wall space needed is increased by 4in^2
original area:
A = L*W
A = 6*3 = 18 in^2
new area:
A' = L'*W'
A' = 8*5 = 40 in^2
the difference between these areas is the amount of wall space needed:
40-18 = 22 in^2
thus it's A.
hope this helps~ :)
Thank you Jai
could you look at my other problems?
sure~ :)
To determine how getting the picture framed changes the amount of wall space needed, you need to calculate the difference between the original picture's area and the area of the framed picture.
The original picture's area is calculated by multiplying its length (3 inches) by its width (6 inches), which gives us 3 inches * 6 inches = 18 square inches.
The framed picture's length is increased by 2 inches, making it 3 inches + 2 inches = 5 inches.
The framed picture's width is increased by 2 inches, making it 6 inches + 2 inches = 8 inches.
The area of the framed picture is calculated by multiplying the increased length (5 inches) by the increased width (8 inches), which gives us 5 inches * 8 inches = 40 square inches.
To find out how the wall space needed changed, subtract the original picture's area (18 square inches) from the area of the framed picture (40 square inches): 40 square inches - 18 square inches = 22 square inches.
Therefore, the correct answer is A. The wall needed is increased by 22 square inches.