Chemistry

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What is the heat in Joules required to raise the temperature of 100g H20 from 288K to 308K?

  • Chemistry -

    to get the heat released or absorbed,
    Q = mc(T2-T1)
    where
    m = mass of substance (units in g)
    c = specific heat capacity (units in J/g-K)
    T2 = final temperature
    T1 = initial temperature
    **note: if Q is (-), heat is released and if (+), heat is absorbed

    for water c = 4.184 J/g-K
    substituting,
    Q = 100*4.184*(308-288)
    Q = 8368 J

    hope this helps~ :)

  • Chemistry -

    8368J

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