Applied Physics

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A 10 kilogram object subjected to a 20 Newton force moves across a horizontal frictionless surface in the direction of the force. Before the force was applied, the speed of the object was 2.0 meters/second. When the force is removed the object is traveling at 6.0 meters per second. The initial kinetic energy is 20 J?

  • Applied Physics -

    the kinetic energy = (1/2) m v^2
    initially the speed is 2
    so the initial Ke = (1/2)(10)(4) = 20 Joules

  • Applied Physics -

    Now I suspect you will be asked what the final Ke is
    (1/2)(10)(36) = 180 Joules

    the increase in Ke = 180 - 20 = 160 Joules = work done by force
    = Force*distance
    so distance = 160/20 = 8 meters
    now for time
    Force * time = change in momentum
    20 t = 10(6-2)
    t = 40/20 = 2 seconds

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