Trig
posted by Rachal .
I need help, I don't remember what to do.
Find all solutions of the equation in the interval [0,2pi].
(2cosè+sqrt3)(cscè+1)=0
Write your answer in radians in terms of pi.
If there is more than one solution, separate them with commas.

zero if either
2 cos e + sqrt 3 = 0
or if
csc e = 1
for the first (in quadrants 2 and 3 for  cos)
cos e =  sqrt 3/2
that in degrees is 18030 or 180+30
in radians it is pi +/ pi/6
for the second sin is  so quadrants 3 and 4)
1/sin e = 1
sin e = 1
pi/2 and pi/2 
thanks!
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